Symbol with private identifier argument


I want to create a symbol equal to that of a private MethodMirror’s simplename. However, Symbol’s documentation states the argument of new Symbol must be a valid public identifier. If I try and create a const Symbol('_privateIdentifier') dart editor informs me that evaluation of this constant expression will throw an exception – though the program runs fine, and I am able to use it without any issues.

void main(){
  //error flagged in dart editor, though runs fine.
  const s = const Symbol('_s');
  print(s); //Symbol("_s");

It seems the mirror system uses symbols.

import 'dart:mirrors';
class ClassA{

void main(){
  var classMirror = reflect(new ClassA()).type;
  //Symbol("_privateMethod"), Symbol("ClassA")

Is the documentation/error flagging in dart editor a legacy bug due to an outdated dart analyzer? Or are there plans to enforce this public requirement in future? Is there another way to create a unique identifying symbol that will be minified to the same symbol as the declaration’s simple name


If it doesn’t throw then the VM has a bug in the const Symbol constructor.

The problem is that “_s” does not identify a private variable without also saying which library it belongs to. The symbol constructor has a second argument taking a LibraryMirror for that reason, and passing in a private name without also passing in a mirror should throw.
That’s hard to do in a const constructor without side-stepping the requirements of a const constructor (no executing code!), which is likely why the VM doesn’t handle it. It needs to be special-cased at the compiler level.

You will also find that const Symbol('_s') is not the same as #_s. The latter creates a private symbol for the current library, the former (if it runs) creates a non-private symbol with the name ‘_s’, which is not really useful. For example print(identical(#_s, const Symbol('_s'))); prints false.

Answered By – lrn

Answer Checked By – Timothy Miller (FlutterFixes Admin)

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